How can 30% of nickel in Rossi’s reactor be transmuted into copper and other information on the Energy Catalyzer

From NextBigFuture.com

This is following up on the Rossi and Focardi energy production device, which was demonstrated in January 2011.

There have been more claims of confirmation of the results in Sweden.

1. The industrial 1000 kW plant, a set of three hundred 4 kW reactors, now under construction in Athens, is expected to become operational in October 2011, according to Rossi. The cost of electricity from such plants, if widely used, is expected to be ten times
lower than from our coal plants. Another desirable feature of the claimed reactor is that it “doesn’t produce radioactive waste”.

2. Rossi says that about 30% of nickel was turned into copper, after 6 months of uninterrupted operation. At first glance this seems to agree with calculations based on simple assumptions.

MeV for each Ni transformation

Starting from Ni58 we can obtain Copper formation and its successive decay in Nickel, producing Ni59, Ni60, and Ni62. The chain stops at Cu63 stable.
For simplicity I assume all the Nickel in the reactor in the form Ni58.
For simplicity I suppose for each Ni58 the whole sequence of events from Ni58 to Cu63 and as a rough estimate I calculate the mass defect between (Ni58 plus 5 nucleons) and the final state Cu63.
Ni58 mass is calculated to be 57.95380± 15 amu
The actual mass of a copper-Cu63 nucleus is 62.91367 amu
Mass of Ni58 plus 5 nucleons is 57.95380+5=62.95380 amu
Mass defect is 62.95380-62.91367=0.04013 amu
1 amu = 931 MeV is used as a standard conversion
0.04013×931 MeV=37.36 MeV
So each transformation of Ni58 into Cu63 releases 37.36MeV of nuclear energy.

Nickel consumption
One hundred grams of nickel powder can power a 10 kW unit for a minimum of six months.

How much of Ni58 should be transformed, in six months of continuous operation, in order to generate 10 kW?

10 kW is thermal or electrical power. The nuclear power must be larger. Assume a nuclear power twice:
20 kW = 20,000 J/s = 1.25 x 10**17 MeV/s.
Each transformation of Ni58 into Cu63 releases 37.36MeV of nuclear energy.
The number of Ni58 transformations should thus be equal to (1.25 x 10**17)/37.36 = 3.346 x 10**15 per second.
Multiplying by the number of seconds in six months (1.55 x 10**7) the total number of transformed Ni58 nuclei is 5.186 x 10**22.
This means 5 grams.
The order of magnitude is not exactly the same but seems to be plausible. This means also 5 grams of Nickel in Rossi’s reactor transmuted into (stable) Copper after six months of continuous operation at the rate of 10 kW.

3. Hydrogen/Nickel nuclear reaction is believed to be the mechanism.

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