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Why Phi? – a long-term Jupiter-Saturn-Uranus model

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Here we find a match between the orbit numbers of Jupiter, Saturn and Uranus and see what that might tell us about certain patterns in the solar system.

715 U = 60072.044 years
2040 S = 60072.895 years
5064 J = 60072.282 years
Data source: Nasa/JPL – Planets and Pluto: Physical Characteristics

The Jupiter-Saturn part of the chart derives directly from this earlier Talkshop post:
Why Phi? – Jupiter, Saturn and the de Vries cycle

Jupiter-Saturn-Earth orbits chart

The numbers are simply multiplied by 24 to obtain the match with the Uranus orbits:
2503 E * 24 = 60072y
85 S * 24 = 2040 S
211 J * 24 = 5064 J
126 J-S * 24 = 3024 J-S

So there’s a match between J, S and U but also a few other points:

715 U = 55 * 13 (Fibonacci numbers)
3024 J-S = 144 * 21 (Fibonacci numbers)
2040 S = 34 * 5 * 3 * 2 * 2 (Fibonacci numbers)

24 * 2503y = 25 * 2402.88y
This result corresponds to the long-term solar inertial motion cycle referred to by Charvatova:
Responses of the basic cycles of 178.7 and 2402 yr in solar–terrestrial phenomena during the Holocene
by I. Charvátová and P. Hejda
Pattern Recogn. Phys., 2, 21–26, 2014

This period of 60072 years thus provides another link between the de Vries cycle and solar inertial motion, in addition to: 6 de Vries = 7 Jose cycles.

Note that 3024 J-S (see chart) = 144 * 21, and 21 J-S = 2 de Vries cycles, so 60072y = 288 de Vries according to this model.
– – –
Regarding the Phi aspect:
1 Uranus orbit = 4.2294~ J-S conjunctions
Phi³ = 4.236~ (> 99.84% match)

Dividing the chart numbers by 5:
143 U (13 * 11) = 408 S (34 * 12)
1 U = (13/34 * 11/12) S
13/34 is a Fibonacci equivalent of 1/Phi²

Alternatively, 1 U = 2.8531064 S
2.8531064 * (11/12) = 2.6153475
34/13 = 2.6153846 (> 99.998% match)


Source: https://tallbloke.wordpress.com/2018/07/22/why-phi-a-long-term-jupiter-saturn-uranus-model/


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